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	<title>Comments on: How to subnet an IP address the easy way</title>
	<atom:link href="http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/feed" rel="self" type="application/rss+xml" />
	<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php</link>
	<description>I search, I bookmark, I write, You learn.</description>
	<lastBuildDate>Mon, 05 Jul 2010 13:59:51 -0500</lastBuildDate>
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		<item>
		<title>By: Andrea</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1273</link>
		<dc:creator>Andrea</dc:creator>
		<pubDate>Mon, 05 Jul 2010 12:14:14 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1273</guid>
		<description>Assign a 60 host network using the ip block 192.168.1.0/24. Allow 0 and 1 subnets? Please can you help me out on how to assign this from the 1st host to the 60th host. Thanks..</description>
		<content:encoded><![CDATA[<p>Assign a 60 host network using the ip block 192.168.1.0/24. Allow 0 and 1 subnets? Please can you help me out on how to assign this from the 1st host to the 60th host. Thanks..</p>
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	<item>
		<title>By: Andrea</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1272</link>
		<dc:creator>Andrea</dc:creator>
		<pubDate>Mon, 05 Jul 2010 12:12:42 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1272</guid>
		<description>Assign a 60 host network using the ip block 192.168.1.0/24. Allow 0 and 1 subnets? Please can you help me out on how to assign this from the 1st host to the 60th host. Thanks.</description>
		<content:encoded><![CDATA[<p>Assign a 60 host network using the ip block 192.168.1.0/24. Allow 0 and 1 subnets? Please can you help me out on how to assign this from the 1st host to the 60th host. Thanks.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Brian</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1262</link>
		<dc:creator>Brian</dc:creator>
		<pubDate>Tue, 15 Jun 2010 19:27:31 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1262</guid>
		<description>@ mike: in your example 216.205.247.24/27 the /27 part represents a 27 bit subnet mask (i.e. 255.255.255.224) which would borrow 8 host bits from a class C IP address and give you 32 hosts per subnet. 

So the subnet addresses would be 216.205.247.0, .32, .64, .96, .128, .160, .192, and .224. The IP address you listed (216.205.247.24) would fall in the first subnet (216.205.247.0) which would have a range of 216.205.247.1 - 216.205.247.30 (216.205.247.31 would be the broadcast address and cannot be assigned to a host)

Hope that helps!</description>
		<content:encoded><![CDATA[<p>@ mike: in your example 216.205.247.24/27 the /27 part represents a 27 bit subnet mask (i.e. 255.255.255.224) which would borrow 8 host bits from a class C IP address and give you 32 hosts per subnet. </p>
<p>So the subnet addresses would be 216.205.247.0, .32, .64, .96, .128, .160, .192, and .224. The IP address you listed (216.205.247.24) would fall in the first subnet (216.205.247.0) which would have a range of 216.205.247.1 &#8211; 216.205.247.30 (216.205.247.31 would be the broadcast address and cannot be assigned to a host)</p>
<p>Hope that helps!</p>
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	</item>
	<item>
		<title>By: mike</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1237</link>
		<dc:creator>mike</dc:creator>
		<pubDate>Thu, 15 Apr 2010 11:49:36 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1237</guid>
		<description>need to find the network address,subnet mask, first available host, broadcast address, and last available host for the IP address 216.205.247.24/27 can anyone help me please.</description>
		<content:encoded><![CDATA[<p>need to find the network address,subnet mask, first available host, broadcast address, and last available host for the IP address 216.205.247.24/27 can anyone help me please.</p>
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	<item>
		<title>By: shinji1212</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1234</link>
		<dc:creator>shinji1212</dc:creator>
		<pubDate>Sun, 11 Apr 2010 14:58:11 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1234</guid>
		<description>how would go about doing this: use the address space 192.168.1.0/24

Vlan 15: needs space for 100 hosts?</description>
		<content:encoded><![CDATA[<p>how would go about doing this: use the address space 192.168.1.0/24</p>
<p>Vlan 15: needs space for 100 hosts?</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Pepilepew</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1210</link>
		<dc:creator>Pepilepew</dc:creator>
		<pubDate>Sun, 24 Jan 2010 00:23:35 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1210</guid>
		<description>Please correct me if I am wrong. 

This IP address is a class C with a mast of 28 which means 4 bits of network and 4 bits of subnets.  

 

128    64  32 16   8   4   2   1 

 1      1   1  1   0   0   0   0 



Given the ip address 209.46.195.123/28

why would the network be 209.46.195.112

why would the 1st host be 209.46.195.113 

why would the last host be 209.46.195.126

why would the b-cast be 209.46.195.127


Can you please explain.  Thank you.</description>
		<content:encoded><![CDATA[<p>Please correct me if I am wrong. </p>
<p>This IP address is a class C with a mast of 28 which means 4 bits of network and 4 bits of subnets.  </p>
<p>128    64  32 16   8   4   2   1 </p>
<p> 1      1   1  1   0   0   0   0 </p>
<p>Given the ip address 209.46.195.123/28</p>
<p>why would the network be 209.46.195.112</p>
<p>why would the 1st host be 209.46.195.113 </p>
<p>why would the last host be 209.46.195.126</p>
<p>why would the b-cast be 209.46.195.127</p>
<p>Can you please explain.  Thank you.</p>
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	<item>
		<title>By: hassan hassan</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1207</link>
		<dc:creator>hassan hassan</dc:creator>
		<pubDate>Mon, 18 Jan 2010 14:31:14 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1207</guid>
		<description>for novice networking engineer, the post is completely valuable for subnetting. really, i&#039;m really happy for this intelligent tools.</description>
		<content:encoded><![CDATA[<p>for novice networking engineer, the post is completely valuable for subnetting. really, i&#8217;m really happy for this intelligent tools.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Morgan</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1206</link>
		<dc:creator>Morgan</dc:creator>
		<pubDate>Mon, 18 Jan 2010 03:19:55 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1206</guid>
		<description>This post is excellent. I&#039;m now using these instructions to teach a class. If you want some practice with instant feedback, try reading this post, then heading here:

http://faculty.valleycollege.net/rpowell/jscript/subnet2.htm

You can generate examples and practice. Do this for an hour, and you&#039;ll feel like an expert.</description>
		<content:encoded><![CDATA[<p>This post is excellent. I&#8217;m now using these instructions to teach a class. If you want some practice with instant feedback, try reading this post, then heading here:</p>
<p><a href="http://faculty.valleycollege.net/rpowell/jscript/subnet2.htm" rel="nofollow" onclick="javascript:urchinTracker ('/outbound/comment/faculty.valleycollege.net');">http://faculty.valleycollege.net/rpowell/jscript/subnet2.htm</a></p>
<p>You can generate examples and practice. Do this for an hour, and you&#8217;ll feel like an expert.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: harish</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1204</link>
		<dc:creator>harish</dc:creator>
		<pubDate>Sat, 09 Jan 2010 04:37:37 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1204</guid>
		<description>I want to subnet A,B,C classes to classless addresses please send my step by step information about it.</description>
		<content:encoded><![CDATA[<p>I want to subnet A,B,C classes to classless addresses please send my step by step information about it.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: saleem</title>
		<link>http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php/comment-page-1#comment-1198</link>
		<dc:creator>saleem</dc:creator>
		<pubDate>Thu, 31 Dec 2009 07:56:53 +0000</pubDate>
		<guid isPermaLink="false">http://www.searchmarked.com/networking/how-to-subnet-an-ip-address-the-easy-way.php#comment-1198</guid>
		<description>the chart is very best way to remember the mask thanks</description>
		<content:encoded><![CDATA[<p>the chart is very best way to remember the mask thanks</p>
]]></content:encoded>
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